Consider the Punnett Square, shown below:Ann Auman. Created for Albert.io. Copyright 2018. All rights reserved.In this situation, the dominant allele (A)(A) codes for pointy ears, and the recessive allele (a)(a) codes for round ears. The first child of couple shown in the Punnett Square has pointy ears.What were the chances that the couple's second child will also have pointy ears?Elimination ToolSelect one answerA25%25%B50%50%C75%75%D100%
Question
Consider the Punnett Square, shown below:Ann Auman. Created for Albert.io. Copyright 2018. All rights reserved.In this situation, the dominant allele (A)(A) codes for pointy ears, and the recessive allele (a)(a) codes for round ears. The first child of couple shown in the Punnett Square has pointy ears.What were the chances that the couple's second child will also have pointy ears?Elimination ToolSelect one answerA25%25%B50%50%C75%75%D100%
Solution
The Punnett Square is not visible in your question, but I can give you a general answer based on typical Punnett Square outcomes.
If one parent has a homozygous dominant genotype (AA) and the other parent has a homozygous recessive genotype (aa), all of their children will have pointy ears because they will all inherit the dominant allele (A) from the first parent and the recessive allele (a) from the second parent, resulting in a heterozygous genotype (Aa). In this case, the chance of the second child having pointy ears is 100%.
If both parents have a heterozygous genotype (Aa), the chances of their children inheriting at least one dominant allele (A) and therefore having pointy ears is 75%. This is because there are four possible combinations of alleles that the child could inherit: AA, Aa, aA, and aa. Three out of these four combinations include at least one dominant allele (A).
If one parent has a homozygous dominant genotype (AA) and the other parent has a heterozygous genotype (Aa), the chances of their children inheriting at least one dominant allele (A) and therefore having pointy ears is 100%. This is because all possible combinations of alleles that the child could inherit from these parents include at least one dominant allele (A).
If one parent has a homozygous recessive genotype (aa) and the other parent has a heterozygous genotype (Aa), the chances of their children inheriting at least one dominant allele (A) and therefore having pointy ears is 50%. This is because there are two possible combinations of alleles that the child could inherit from these parents: Aa and aa. Only one out of these two combinations includes a dominant allele (A).
So, without the Punnett Square, I can't give a specific answer, but these are the possible outcomes based on different combinations of parental genotypes.
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