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The acceleration of a freely falling body does not depend on the mass of the body. Prove this.

Question

The acceleration of a freely falling body does not depend on the mass of the body. Prove this.

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Solution

Sure, here's a step-by-step proof:

  1. The force acting on a freely falling body due to gravity is given by Newton's second law of motion, F = ma, where F is the force, m is the mass of the body, and a is the acceleration.

  2. The force of gravity is also given by the equation F = mg, where g is the acceleration due to gravity.

  3. Setting these two equations equal to each other, we get ma = mg.

  4. Dividing both sides by m, we get a = g.

This shows that the acceleration of a freely falling body is equal to the acceleration due to gravity, g, which is a constant (approximately 9.8 m/s^2 on the surface of the Earth). This is independent of the mass of the body, proving the statement.

This problem has been solved

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The acceleration of freely falling bodies due the force of attraction of the other body is called Acceleration due to gravity. It is a constant quantity for a given attracting body at a given place. Like for earth on or near its surface, the average value of acceleration due to gravity is 9.8 m/s

A freely falling body has a constant acceleration of 9.8 m/s2. This means that: Group of answer choicesthe acceleration of the body increases by 9.8 m/s2 during each secondthe speed of the body increases by 9.8 m/s during each secondthe body falls 9.8 m during each secondthe acceleration of the body decreases by 9.8 m/s2 during each secondthe body falls 9.8 m during the first second

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