N2(g) + 3H2(g) --> 2NH3(g) + 91.8kJ what is true about this system?A exothermic and ∆H= -91.8 kJB exothermic and ∆H= +91.8 kJC endothermic and ∆H= -91.8 kJD endothermic and ∆H= +91.8 kJ
Question
N2(g) + 3H2(g) --> 2NH3(g) + 91.8kJ what is true about this system?A exothermic and ∆H= -91.8 kJB exothermic and ∆H= +91.8 kJC endothermic and ∆H= -91.8 kJD endothermic and ∆H= +91.8 kJ
Solution
The correct answer is A. This is an exothermic reaction and ∆H= -91.8 kJ.
In an exothermic reaction, heat is released into the surroundings, which is indicated by the negative ∆H value. The negative sign shows that the system is losing heat. The 91.8 kJ of energy is released when 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas to form 2 moles of ammonia gas.
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