Consider the following directed graph: A->B B->D D->F A->C C->E C->B Which of the following represents a breadth-first traversal of the above graph, when starting at node 'a'? Group of answer choices a, b, c, d, e, f a, b, d, f, c, e a, c, e, b, d, f BFS will not work on this graph

The correct answer is: a, b, c, d, e, f

Here's why:

A breadth-first traversal of a graph starts at a given node (in this case, 'a'), explores the neighbor nodes at the present depth prior to moving on to nodes at the next depth level.

1. We start at node 'a'. The neighbors of 'a' are 'b' and 'c'. We add them to the traversal in the order they are encountered. So, the traversal so far is: a, b, c

2. Next, we move to 'b'. The neighbor of 'b' is 'd', which hasn't been visited yet. So, we add 'd' to the traversal. The traversal so far is: a, b, c, d

3. We then move to 'c'. The neighbors of 'c' are 'e' and 'b'. But 'b' has already been visited, so we only add 'e' to the traversal. The traversal so far is: a, b, c, d, e

4. Next, we move to 'd'. The neighbor of 'd' is 'f', which hasn't been visited yet. So, we add 'f' to the traversal. The traversal so far is: a, b, c, d, e, f

5. Finally, we move to 'e' and 'f', but neither of them have any unvisited neighbors. So, the final breadth-first traversal is: a, b, c, d, e, f