Given the functionf(x)=2000[1.13]x+380Find f(5).
Question
Given the functionf(x)=2000[1.13]x+380Find f(5).
Solution
To find the value of f(5), you need to substitute x = 5 into the function f(x) = 2000[1.13]^x + 380.
Step 1: Substitute x = 5 into the function f(5) = 2000[1.13]^5 + 380
Step 2: Calculate the value of [1.13]^5 [1.13]^5 = 1.88 (approximately)
Step 3: Multiply 2000 by 1.88 2000 * 1.88 = 3760
Step 4: Add 380 to 3760 3760 + 380 = 4140
So, f(5) = 4140.
Similar Questions
Question 5 of 10Use the function below to find F(3).F(x) = 3xA.6B.27C.81D.9
Evaluate the function f(x) at the given numbers. (Round your answers to six decimal places.)f(x) = 5ex − 5 − 5xx2, x = 1, 0.5, 0.1, 0.05, 0.01, −1, −0.5, −0.1, −0.05, −0.01f(1) = f(0.5) = f(0.1) = f(0.05) = f(0.01) = f(−1) = f(−0.5) = f(−0.1) = f(−0.05) = f(−0.01) = Guess the value of the limit of f(x) as x approaches 0. (Round your answer to six decimal places. If an answer does not exist, enter DNE.)lim x→0 5ex − 5 − 5xx2 =
If 10f(x) dx = 390 and 10g(x) dx = 16,0 find 10[4f(x) + 6g(x)] dx.0
Find 7f(x) dx0 iff(x) = 5 for x < 5x for x ≥ 5.
The result of increasing the quantity x by 400% is60. What is the value of x ?A) 12B) 15C) 240D) 340
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.