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19๐‘ฅ โ‰ก 4 (๐‘š๐‘œ๐‘‘ 141)

Question

19๐‘ฅ โ‰ก 4 (๐‘š๐‘œ๐‘‘ 141)

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Solution

To solve the equation 19๐‘ฅ โ‰ก 4 (๐‘š๐‘œ๐‘‘ 141), we need to find the value of ๐‘ฅ that satisfies the congruence.

Step 1: Find the modular inverse of 19 modulo 141. To find the modular inverse, we need to find a number ๐‘Ž such that (19๐‘Ž) โ‰ก 1 (๐‘š๐‘œ๐‘‘ 141). In other words, we need to find a number ๐‘Ž such that (19๐‘Ž) % 141 = 1.

Using the Extended Euclidean Algorithm, we can find that the modular inverse of 19 modulo 141 is 59. Therefore, we can rewrite the congruence as:

๐‘ฅ โ‰ก (4 * 59) % 141

Step 2: Simplify the right-hand side of the congruence. Calculating (4 * 59) % 141, we get:

๐‘ฅ โ‰ก 236 % 141

Step 3: Find the remainder of 236 divided by 141. Dividing 236 by 141, we get a quotient of 1 and a remainder of 95. Therefore, we can rewrite the congruence as:

๐‘ฅ โ‰ก 95 (๐‘š๐‘œ๐‘‘ 141)

So, the solution to the congruence 19๐‘ฅ โ‰ก 4 (๐‘š๐‘œ๐‘‘ 141) is ๐‘ฅ โ‰ก 95 (๐‘š๐‘œ๐‘‘ 141).

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