Determine the magnitude and direction of the electric field that is created at a distance of 2.5 mm from a negative point charge of 7.6 nC
Question
Determine the magnitude and direction of the electric field that is created at a distance of 2.5 mm from a negative point charge of 7.6 nC
Solution
To solve this problem, we will use Coulomb's Law, which states that the electric field (E) created by a point charge (q) at a distance (r) is given by:
E = k * |q| / r^2
where k is Coulomb's constant (8.99 * 10^9 N m^2/C^2), |q| is the absolute value of the charge, and r is the distance from the charge.
Step 1: Convert the distance from mm to meters. 2.5 mm = 2.5 * 10^-3 m
Step 2: Convert the charge from nC to C. 7.6 nC = 7.6 * 10^-9 C
Step 3: Substitute the values into the equation. E = (8.99 * 10^9 N m^2/C^2) * (7.6 * 10^-9 C) / (2.5 * 10^-3 m)^2
Step 4: Calculate the magnitude of the electric field.
The direction of the electric field is always from positive to negative charges. Since we have a negative charge, the electric field direction is towards the charge.
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