Consider the table EMPLOYEE(empId, name, department, salary) and the two queries Q1 ,Q2 below. Assuming that department D5 has more than one employee, and we want to find the employees who get higher salary than anyone in department D5, which one of the statements is TRUE for any arbitrary employee table?Q1 : SELECT e.empId FROM employee e WHERE NOT EXIST (SELECT * From employee s where s.department = “D5” AND s.salary >=e.salary)Q2 : SELECT e.empIdFROM employee eWHERE e.salary > Any (Select distinct salary From employee s Where s.department = “D5”)Q1 is the correct queryQ2 is the correct queryBoth Q1 and Q2 produce the same answer.Neither Q1 nor Q2 is the correct query
Question
Consider the table EMPLOYEE(empId, name, department, salary) and the two queries Q1 ,Q2 below. Assuming that department D5 has more than one employee, and we want to find the employees who get higher salary than anyone in department D5, which one of the statements is TRUE for any arbitrary employee table?Q1 : SELECT e.empId FROM employee e WHERE NOT EXIST (SELECT * From employee s where s.department = “D5” AND s.salary >=e.salary)Q2 : SELECT e.empIdFROM employee eWHERE e.salary > Any (Select distinct salary From employee s Where s.department = “D5”)Q1 is the correct queryQ2 is the correct queryBoth Q1 and Q2 produce the same answer.Neither Q1 nor Q2 is the correct query
Solution
Q2 is the correct query.
Here's why:
Q1: This query selects employees who earn more than all employees in department D5. The NOT EXISTS clause will return true only if the subquery returns no rows. This means that it will only return employees who earn more than every employee in department D5.
Q2: This query selects employees who earn more than any employee in department D5. The ANY operator returns true if any subquery values meet the condition. This means it will return employees who earn more than at least one employee in department D5.
So, if we want to find employees who get higher salary than anyone in department D5, Q2 is the correct query.
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