This problem is about maximizing the total price of tickets sold from multiple counters. Here's a step-by-step solution:

1. Parse the input: The first line of input gives the number of test cases. Each test case is defined by two lines. The first line of the test case gives the number of counters and the number of tickets to be sold. The second line gives the number of tickets at each counter.

2. For each test case, follow these steps:

a. Create a max heap to store the number of tickets at each counter. The max heap is used because we always want to sell the ticket from the counter that has the most tickets left, as that will give us the maximum price.

b. While there are still tickets to be sold (i.e., K 0), do the following:

i. Remove the top element from the max heap (this is the counter with the most tickets left).

ii. Subtract one from the number of tickets at this counter (since we're selling one ticket), and add the original number of tickets at this counter to the total price (since the price of a ticket is equal to the number of tickets left at the counter before the sale).

iii. If there are still tickets left at this counter after the sale, add this counter back into the max heap.

iv. Subtract one from K (since we've sold one ticket).

3. The total price calculated in step 2 is the maximum amount that can be collected for the given test case.

4. Repeat steps 2 and 3 for each test case.

5. Print the maximum amount collected for each test case.

This solution works because it always sells the ticket that will bring in the most money (i.e., the ticket from the counter with the most tickets left). This ensures that the total price is maximized.

Question

This problem is about maximizing the total price of tickets sold from multiple counters. Here's a step-by-step solution:

1. Parse the input: The first line of input gives the number of test cases. Each test case is defined by two lines. The first line of the test case gives the number of counters and the number of tickets to be sold. The second line gives the number of tickets at each counter.

2. For each test case, follow these steps:

a. Create a max heap to store the number of tickets at each counter. The max heap is used because we always want to sell the ticket from the counter that has the most tickets left, as that will give us the maximum price.

b. While there are still tickets to be sold (i.e., K > 0), do the following:

i. Remove the top element from the max heap (this is the counter with the most tickets left).

ii. Subtract one from the number of tickets at this counter (since we're selling one ticket), and add the original number of tickets at this counter to the total price (since the price of a ticket is equal to the number of tickets left at the counter before the sale).

iii. If there are still tickets left at this counter after the sale, add this counter back into the max heap.

iv. Subtract one from K (since we've sold one ticket).

3. The total price calculated in step 2 is the maximum amount that can be collected for the given test case.

4. Repeat steps 2 and 3 for each test case.

5. Print the maximum amount collected for each test case.

This solution works because it always sells the ticket that will bring in the most money (i.e., the ticket from the counter with the most tickets left). This ensures that the total price is maximized.

Knowee AI · Accepted Answer