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Let D be a simply connected domain and suppose fo (z) is analytic in a domain Do D. If the function element (fo. Do) can be analytically continued along every curve in D, then there does not exists any single-valued function f(z) that is analytic throughout D with f(z) = fo(z) in Do. 1) True 2) False

Question

Let D be a simply connected domain and suppose fo (z) is analytic in a domain Do D. If the function element (fo. Do) can be analytically continued along every curve in D, then there does not exists any single-valued function f(z) that is analytic throughout D with f(z) = fo(z) in Do. 1) True 2) False

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Solution

  1. False. If a function f(z) is analytic in a domain D and matches with fo(z) in a subdomain Do of D, then it is the analytic continuation of fo(z) in D. The condition that the function can be analytically continued along every curve in D does not prevent the existence of such a function f(z). Therefore, there can exist a single-valued function f(z) that is analytic throughout D with f(z) = fo(z) in Do.

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