The present ages of three persons are in proportions 4 : 7 : 9.Eight years ago, the sum of their ages was 76.Find their present ages (in years).8,20,2812,21,2720,35,45None of these
Question
The present ages of three persons are in proportions 4 : 7 : 9.Eight years ago, the sum of their ages was 76.Find their present ages (in years).8,20,2812,21,2720,35,45None of these
Solution
Let's denote the present ages of the three persons as 4x, 7x, and 9x.
According to the problem, eight years ago, the sum of their ages was 76. So, we can write the equation as:
(4x - 8) + (7x - 8) + (9x - 8) = 76
Solving this equation, we get:
20x - 24 = 76
Adding 24 to both sides, we get:
20x = 100
Dividing both sides by 20, we get:
x = 5
So, the present ages of the three persons are 4x = 20 years, 7x = 35 years, and 9x = 45 years.
Therefore, the correct answer is 20, 35, 45.
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