To solve this problem, we need to convert the given integer into binary and then count the number of trailing zeroes. Here is a step-by-step solution in Python:

```python
def count_trailing_zeroes(A):
# Convert the integer to binary and remove the '0b' prefix
binary = bin(A)[2:]

# Reverse the binary string to count trailing zeroes
binary = binary[::-1]

# Initialize count of trailing zeroes
count = 0

# Iterate over the reversed binary string
for bit in binary:
# If the bit is '0', increment the count
if bit == '0':
count += 1
# If the bit is '1', break the loop as we have counted all trailing zeroes
else:
break

# Return the count of trailing zeroes
return count
```

You can call this function with an integer to get the count of trailing zeroes. For example:

```python
print(count_trailing_zeroes(18)) # Output: 1
print(count_trailing_zeroes(8)) # Output: 3
```

This function works by first converting the integer to a binary string. It then reverses this string so that the trailing zeroes in the original binary string are now leading zeroes in the reversed string. The function then iterates over the reversed string, counting zeroes until it encounters a '1'. At this point, it has counted all the trailing zeroes in the original binary string, so it breaks the loop and

Question

To solve this problem, we need to convert the given integer into binary and then count the number of trailing zeroes. Here is a step-by-step solution in Python:

```python
def count_trailing_zeroes(A):
    # Convert the integer to binary and remove the '0b' prefix
    binary = bin(A)[2:]
    
    # Reverse the binary string to count trailing zeroes
    binary = binary[::-1]
    
    # Initialize count of trailing zeroes
    count = 0
    
    # Iterate over the reversed binary string
    for bit in binary:
        # If the bit is '0', increment the count
        if bit == '0':
            count += 1
        # If the bit is '1', break the loop as we have counted all trailing zeroes
        else:
            break
    
    # Return the count of trailing zeroes
    return count
```

You can call this function with an integer to get the count of trailing zeroes. For example:

```python
print(count_trailing_zeroes(18))  # Output: 1
print(count_trailing_zeroes(8))   # Output: 3
```

This function works by first converting the integer to a binary string. It then reverses this string so that the trailing zeroes in the original binary string are now leading zeroes in the reversed string. The function then iterates over the reversed string, counting zeroes until it encounters a '1'. At this point, it has counted all the trailing zeroes in the original binary string, so it breaks the loop and

Knowee AI · Accepted Answer

To solve this problem, we need to convert the given integer into binary and then count the number of trailing zeroes. Here is a step-by-step solution in Python:

```python
def count_trailing_zeroes(A):
    # Convert the integer to binary and remove the '0b' prefix
    binary = bin(A)[2:]
    
    # Reverse the binary string to count trailing zeroes
    binary = binary[::-1]
    
    # Initialize count of trailing zeroes
    count = 0
    
    # Iterate over the reversed binary string
    for bit in binary:
        # If the bit is '0', increment the count
        if bit == '0':
            count += 1
        # If the bit is '1', break the loop as we have counted all trailing zeroes
        else:
            break
    
    # Return the count of trailing zeroes
    return count
```

You can call this function with an integer to get the count of trailing zeroes. For example:

```python
print(count_trailing_zeroes(18))  # Output: 1
print(count_trailing_zeroes(8))   # Output: 3
```

This function works by first converting the integer to a binary string. It then reverses this string so that the trailing zeroes in the original binary string are now leading zeroes in the reversed string. The function then iterates over the reversed string, counting zeroes until it encounters a '1'. At this point, it has counted all the trailing zeroes in the original binary string, so it breaks the loop and

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