2. Draw an acute-angled ∆PQR. Draw all of its altitudes. Name the point of concurrence as ‘O’.
Question
- Draw an acute-angled ∆PQR. Draw all of its altitudes. Name the point of concurrence as ‘O’.
Solution
Step 1: Draw a triangle PQR with an acute angle.
Step 2: An altitude of a triangle is a line which passes through a vertex of the triangle and is perpendicular to the opposite side. So, draw the three altitudes from each vertex (P, Q, R) to their opposite sides.
Step 3: The point where all three altitudes intersect is called the orthocenter. Mark this point as 'O'.
Remember, in an acute-angled triangle like ∆PQR, the orthocenter 'O' will always be inside the triangle.
Similar Questions
4. Draw an obtuse-angled ∆LMN. Draw its altitudes and denote the orthocenter by ‘O’.
6. Draw an isosceles triangle. Draw all of its medians and altitudes. Write your observation about their points of concurrence.
1. In ∆LMN, …… is an altitude and …… is a median. (Write the names of appropriate segments.)
3. Draw an obtuse-angled ∆STV. Draw its medians and show the centroid.
3. This referred to as horizontal lines specifying the north-south position.*1 pointLongitudeEquatorLatitude
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