Rahul & Simran are at a distance of 1200 m. They start towards each other with speeds of 23kmph & 28kmph. As they start, a bird sitting on the cap of Rahul, starts flying towards Simran, touches Simran & then returns towards Rahul & so on, till they meet. What is the distance (in m) travelled by the bird, if its speed is 204 kmph?

Sure, let's solve this step by step:

1. First, we need to find out how long it will take for Rahul and Simran to meet. They are moving towards each other, so we add their speeds together. Convert the speeds from km/h to m/s by multiplying by (1000/3600) because 1 km = 1000 m and 1 hour = 3600 seconds. So, Rahul's speed is 23*(1000/3600) = 6.39 m/s and Simran's speed is 28*(1000/3600) = 7.78 m/s. Their combined speed is 6.39 + 7.78 = 14.17 m/s.

2. The distance between them is 1200 m. So, the time it takes for them to meet is the distance divided by their combined speed, which is 1200 / 14.17 = 84.64 seconds.

3. Now, we need to find out how far the bird travels in this time. The bird's speed is 204 km/h, which is 204*(1000/3600) = 56.67 m/s.

4. The distance the bird travels is its speed multiplied by the time, which is 56.67 * 84.64 = 4796.37 m.

So, the bird travels approximately 4796.37 meters.