A simple pendulum of length 2.00 m has a mass of 100 g attached. It is drawn back 30.0° and then released. What is the maximum speed of the mass?Select one:a.1.62 m/sb.4.58 m/sc.1.14 m/sd.2.29 m/s
Question
A simple pendulum of length 2.00 m has a mass of 100 g attached. It is drawn back 30.0° and then released. What is the maximum speed of the mass?Select one:a.1.62 m/sb.4.58 m/sc.1.14 m/sd.2.29 m/s
Solution
To solve this problem, we need to use the principle of conservation of energy. The pendulum starts with potential energy and no kinetic energy at the top of its swing, and it has maximum kinetic energy and no potential energy at the bottom of its swing.
-
First, we calculate the height (h) at which the pendulum bob is initially held. This can be found using the equation h = L - Lcosθ, where L is the length of the pendulum and θ is the angle. Substituting the given values, we get h = 2.00 m - 2.00 m cos(30.0°) = 0.133974596 m.
-
Next, we calculate the initial potential energy (PE) of the pendulum bob using the equation PE = mgh, where m is the mass of the bob, g is the acceleration due to gravity, and h is the height we just calculated. Substituting the given values, we get PE = 0.1 kg * 9.8 m/s² * 0.133974596 m = 0.131334584 J.
-
Since the pendulum bob has no kinetic energy at the top of its swing, all of its energy is potential energy. Therefore, at the bottom of its swing, all of this energy will have been converted into kinetic energy (KE).
-
We can find the maximum speed of the pendulum bob by setting its kinetic energy equal to the initial potential energy and solving for velocity. The equation for kinetic energy is KE = 1/2 mv². Setting this equal to the initial potential energy, we get 0.131334584 J = 1/2 * 0.1 kg * v².
-
Solving this equation for v, we get v = sqrt((2 * 0.131334584 J) / 0.1 kg) = 1.62 m/s.
So, the maximum speed of the mass is 1.62 m/s. Therefore, the answer is a. 1.62 m/s.
Similar Questions
A simple pendulum, 2.00 m in length, is released from rest when the support string is at an angle of 35.0° from the vertical. What is the speed of the suspended mass at the bottom of the swing? (g = 9.80 m/s2 and ignore air resistance)Select one:a.1.33 m/sb.1.88 m/sc.0.941 m/sd.2.66 m/s
A pendulum of length 1 𝑚 is releasedfrom 𝜃 = 60°. The rate of change ofspeed of the bob at 𝜃 = 30° is (𝑔 =10 𝑚𝑠−2).(a) 10 𝑚𝑠−2(b) 7.5 𝑚𝑠−2(c) 5 𝑚𝑠−2(d) 5√3𝑚𝑠−2
A simple pendulum has a mass of 0.27 kg and a length of 1.5 m. It is displaced through an angle of 40° and then released. After a time, the maximum angle of swing is only 14°. How much energy has been lost to friction?Select one:a.0.81 Jb.0.93 Jc.0.12 Jd.1.00 Je.1.05 J
A 75 kg mass is attached to the end of a 5.0 m long metal string which rotates in a horizontal circular path. If the maximum force that the rod can withstand is 8500 N, what is the maximum speed the mass can attain without breaking the string?*1 point0.238 m/s2.38 m/s23.8 m/s238 m/s
A pendulum consists of a 4.00 kg mass suspended at the end of a 75.0 cm thin, massless rod. The pendulum is released from an angle of 20.0 degrees with the vertical. What is the velocity of the pendulum as it passes through the origin?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.