Knowee
Questions
Features
Study Tools

A buffer solution is made up of acetic acid [pKa = 5] having conc. = 1.5 M and sodium acetate having conc. = 0.15 M. What is the number of OH– ions present in 1 litre solution ?10–10 NA10–4 NA10–3 NA10–6 NA

Question

A buffer solution is made up of acetic acid [pKa = 5] having conc. = 1.5 M and sodium acetate having conc. = 0.15 M. What is the number of OH– ions present in 1 litre solution ?10–10 NA10–4 NA10–3 NA10–6 NA

🧐 Not the exact question you are looking for?Go ask a question

Solution

To solve this problem, we need to use the Henderson-Hasselbalch equation, which is pH = pKa + log([A-]/[HA]). In this case, [A-] is the concentration of sodium acetate and [HA] is the concentration of acetic acid.

  1. Substitute the given values into the equation: pH = 5 + log(0.15/1.5) = 5 + log(0.1) = 5 - 1 = 4. So, the pH of the solution is 4.

  2. Now, we need to find the concentration of OH- ions. We know that pH + pOH = 14 at 25 degrees Celsius. So, pOH = 14 - pH = 14 - 4 = 10.

  3. The concentration of OH- ions is given by 10^-pOH. So, [OH-] = 10^-10 M.

  4. To find the number of OH- ions in 1 litre of solution, we multiply the concentration by Avogadro's number (NA), which is approximately 6.022 x 10^23. So, the number of OH- ions is [OH-] x NA = 10^-10 x 6.022 x 10^23 = 6.022 x 10^13.

So, the number of OH- ions present in 1 litre solution is 6.022 x 10^13, which is closest to the option 10^-10 NA.

This problem has been solved

Similar Questions

Acetic acid has a pKa of 4.8. How many milliliters of 0.2 M acetic acid and 0.1 M sodium acetate are required to prepare 1 liter of 0.1 M buffer solution having a pH of 4.8? Question 7 options: 500 ml acetic acid and 250 ml sodium acetate, then 250 ml water 250 ml acetic acid and 250 ml sodium acetate, then 500 ml water 250 ml acetic acid and 500 ml sodium acetate, then 250 ml water 500 ml acetic acid and 500 ml sodium acetate

This question concerns part 1 of this lab.You need to make a buffer solution by mixing both a weak acid and its conjugate base in the right proportions to achieve the desired pH.Your desired target pH is 5.40. You have been provided with 5.00 mL of 0.100 M acetic acid solution.How many moles of sodium acetate do you need to add to this solution to obtain a buffer solution at the desired pH? The pKa of acetic acid is 4.74. Answer

Calculate the pH of a buffer solution prepared by mixing 0.2 moles of acetic acid (CH₃COOH) and 0.2 moles of sodium acetate (CH₃COONa) in enough water to make a total volume of 1 liter. The pKa of acetic acid is 5.42.Select one:a.5.4b.5.8c.6.3d.4.5

What is the final pH of a buffer solution made by mixing 10 mL of 0.6% Acetic Acid (CH3COOH; MW = 60.05; pKa = 4.8) with 50 mL of a 1.36% Sodium Acetate (CH3COONa.3H2O; MW = 136.1) solution?pH = pka + log[salt]/[acid]4.1b.4.5c.5.15d.5.5e.9.8

A buffer mixture of acetic acid and potassium acetate has PH=5.24. The ratio of [CH3COO-]/[CH3COOH] in this buffer is, (pKa=4.74)

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.