Calculate how much storage space is needed to record a 32- bit, 7 khz, stereo music for a duration of 1 hour. (Give in bytes:  put the value without symbol)

To calculate the storage space needed, we need to use the formula:

Storage Space = Bit Depth * Sample Rate * Channels * Time

where:

• Bit Depth is the number of bits in each sample, which is 32 bits in this case.
• Sample Rate is the number of samples per second, which is 7,000 (or 7 kHz) in this case.
• Channels is the number of separate audio signals, which is 2 for stereo sound.
• Time is the duration of the audio in seconds. Since we're looking for an hour, this would be 60 minutes * 60 seconds = 3,600 seconds.

So, the calculation would be:

Storage Space = 32 bits/sample * 7,000 samples/second * 2 * 3,600 seconds

This gives us the total storage space in bits. However, we want the answer in bytes, and there are 8 bits in a byte. So, we divide the total by 8 to convert from bits to bytes:

Storage Space = (32 * 7,000 * 2 * 3,600) / 8 bytes

When you calculate this, you get 3,168,000,000 bytes.

To calculate the storage space needed, we need to use the formula:

Storage Space = Bit Depth * Sample Rate * Channels * Time

where:

• Bit Depth is the number of bits in each sample, which is 32 bits in this case.
• Sample Rate is the number of samples per second, which is 7,000 (or 7 kHz) in this case.
• Channels is the number of separate audio signals, which is 2 for stereo sound.
• Time is the duration of the audio in seconds. Since we're looking for an hour, this would be 60 minutes * 60 seconds = 3,600 seconds.

So, the calculation would be:

Storage Space = 32 bits/sample * 7,000 samples/second * 2 * 3,600 seconds

This gives us the total storage space in bits. However, we want the answer in bytes, and there are 8 bits in a byte. So, we divide the total by 8 to convert from bits to bytes:

Storage Space = (32 * 7,000 * 2 * 3,600) / 8 bytes

Let's calculate that:

Storage Space = 3,168,000,000 bytes

So, you would need approximately 3,168,000,000 bytes of storage space to record a 32-bit, 7 kHz, stereo music for a duration of 1 hour.

To calculate the storage space needed, we need to use the formula:

Storage Space = Bit Depth * Sample Rate * Channels * Time

where:

• Bit Depth is the number of bits in each sample, which is 32 bits in this case.
• Sample Rate is the number of samples per second, which is 7 kHz or 7000 samples per second.
• Channels is the number of separate audio signals, which is 2 for stereo.
• Time is the duration of the audio in seconds. 1 hour is 3600 seconds.

So, the storage space needed is:

Storage Space = 32 bits/sample * 7000 samples/second * 2 * 3600 seconds

However, the result of this calculation will be in bits. Since 1 byte = 8 bits, we need to divide the result by 8 to convert it to bytes.

Let's calculate:

Storage Space = (32 * 7000 * 2 * 3600) / 8

Storage Space = 20160000000 bytes

So, you would need 20160000000 bytes of storage space to record a 32-bit, 7 kHz, stereo music for a duration of 1 hour.

To calculate the storage space needed, we need to use the formula:

Storage Space = Bit Depth * Sample Rate * Channels * Time

where:

• Bit Depth is the number of bits in each sample, which is 32 bits in this case.
• Sample Rate is the number of samples per second, which is 7,000 (7 kHz) in this case.
• Channels is the number of separate audio signals, which is 2 (stereo) in this case.
• Time is the duration of the audio in seconds. Since we have 1 hour, and there are 3600 seconds in an hour, the time is 3600 seconds.

So, the calculation would be:

Storage Space = 32 bits/sample * 7,000 samples/second * 2 * 3600 seconds

However, the result of this calculation will be in bits. Since 1 byte = 8 bits, we need to divide the result by 8 to convert it to bytes.

Let's do the calculation:

Storage Space = (32 * 7,000 * 2 * 3600) / 8

Storage Space = 1008,000,000 bytes

So, you would need 1008,000,000 bytes of storage space to record a 32-bit, 7 kHz, stereo music for a duration of 1 hour.