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(log2 n)999999999 ∈ O(n0.0000000000001)

Question

(log2 n)999999999 ∈ O(n0.0000000000001)

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Solution

The statement is asking if the function (log2 n)^999999999 is in the order of O(n^0.0000000000001).

To answer this, we need to understand the concept of Big O notation. Big O notation is a mathematical notation that describes the limiting behavior of a function when the argument tends towards a particular value or infinity. It is used in computer science to describe the performance or complexity of an algorithm.

In this case, we are comparing the function (log2 n)^999999999 with n^0.0000000000001.

The function (log2 n)^999999999 grows much faster than n^0.0000000000001 as n approaches infinity.

Therefore, we can say that (log2 n)^999999999 is not in the order of O(n^0.0000000000001).

This problem has been solved

Similar Questions

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