parallel plate capacitor is made by stacking n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is C then the resultant capacitance i
Question
parallel plate capacitor is made by stacking n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is C then the resultant capacitance i
Solution
The resultant capacitance of a parallel plate capacitor made by stacking n equally spaced plates connected alternatively depends on whether the stack is connected in series or parallel.
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If the capacitors are connected in series, the total capacitance (C_total) is given by the formula 1/C_total = 1/C1 + 1/C2 + ... + 1/Cn. Since all the capacitors have the same capacitance (C), this simplifies to 1/C_total = n/C. Solving for C_total gives C_total = C/n.
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If the capacitors are connected in parallel, the total capacitance is simply the sum of the individual capacitances: C_total = C1 + C2 + ... + Cn = nC.
So, if the plates are connected alternatively, it means that one plate is connected to the next one in a series arrangement. For n plates, there will be n-1 capacitors in series. Therefore, the resultant capacitance will be C/(n-1).
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