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When 8 coins are tossed simultaneously, in _______ number of the outcomes at most two of the coins will turn up as heads.

Question

When 8 coins are tossed simultaneously, in _______ number of the outcomes at most two of the coins will turn up as heads.

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Solution

To solve this problem, we need to use the concept of combinations in probability.

  1. When no coin turns up as heads: There is only 1 way this can happen, which is when all coins turn up tails.

  2. When exactly one coin turns up as heads: This can happen in 8 ways. This is because there are 8 coins, and any one of them can turn up as heads.

  3. When exactly two coins turn up as heads: This can happen in "8 choose 2" ways. In mathematics, "n choose r" is a way of selecting r items from a larger set of n items. In this case, "8 choose 2" equals 28.

So, the total number of outcomes in which at most two of the coins will turn up as heads is 1 (no heads) + 8 (one head) + 28 (two heads) = 37.

This problem has been solved

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