The inverse function of 𝑦=log2(𝑥) is 𝑦=2^𝑥.

Here's the step by step process:

1. Start with the function 𝑦=log2(𝑥).
2. To find the inverse, we switch the roles of 𝑦 and 𝑥 to get 𝑥=log2(𝑦).
3. Then, we solve for 𝑦. In this case, we use the fact that if 𝑎=logb(𝑐), then 𝑏^𝑎=𝑐.
4. So, we rewrite 𝑥=log2(𝑦) as 2^𝑥=𝑦.
5. Therefore, the inverse function of 𝑦=log2(𝑥) is 𝑦=2^𝑥.

Question

The inverse function of 𝑦=log2(𝑥) is 𝑦=2^𝑥.

Here's the step by step process:

1. Start with the function 𝑦=log2(𝑥).
2. To find the inverse, we switch the roles of 𝑦 and 𝑥 to get 𝑥=log2(𝑦).
3. Then, we solve for 𝑦. In this case, we use the fact that if 𝑎=logb(𝑐), then 𝑏^𝑎=𝑐.
4. So, we rewrite 𝑥=log2(𝑦) as 2^𝑥=𝑦.
5. Therefore, the inverse function of 𝑦=log2(𝑥) is 𝑦=2^𝑥.

Knowee AI · Accepted Answer

The inverse function of 𝑦=log2(𝑥) is 𝑦=2^𝑥.

Here's the step by step process:

1. Start with the function 𝑦=log2(𝑥).
2. To find the inverse, we switch the roles of 𝑦 and 𝑥 to get 𝑥=log2(𝑦).
3. Then, we solve for 𝑦. In this case, we use the fact that if 𝑎=logb(𝑐), then 𝑏^𝑎=𝑐.
4. So, we rewrite 𝑥=log2(𝑦) as 2^𝑥=𝑦.
5. Therefore, the inverse function of 𝑦=log2(𝑥) is 𝑦=2^𝑥.

What is the inverse function of 𝑦=log2(𝑥)?

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