If 27th March, 2007 was a Tuesday, then which day of the week was 23rd October 2008?

To find the day of the week for 23rd October 2008, we can use the concept of 'odd days'. Odd days are the days that exceed complete weeks. Here are the steps:

1. Calculate the number of odd days from 27th March 2007 to 31st December 2007.

   • March has 5 odd days (31-27+1 = 5, because we're counting both 27th and 31st)
   • April has 2 odd days (30 days = 4 weeks + 2 days)
   • May has 3 odd days
   • June has 2 odd days
   • July has 3 odd days
   • August has 3 odd days
   • September has 2 odd days
   • October has 3 odd days
   • November has 2 odd days
   • December has 3 odd days
   • Total odd days in 2007 after 27th March = 5+2+3+2+3+3+2+3+2+3 = 28 = 0 odd days (because 28 is a multiple of 7)

2. Calculate the number of odd days in the year 2008 until 23rd October.

   • 2008 is a leap year. So, February has 1 odd day.
   • All other months have the same number of odd days as in step 1.
   • Total odd days in 2008 until 23rd October = 3 (January) + 1 (February) + 3 (March) + 2 (April) + 3 (May) + 2 (June) + 3 (July) + 3 (August) + 2 (September) + 0 (October, because we're only counting until 23rd) = 22 = 1 odd day (because 22 divided by 7 leaves a remainder of 1)

3. Add the total odd days.

   • Total odd days = 0 (from 2007) + 1 (from 2008) = 1

4. The day of the week 1 day after Tuesday is Wednesday.

So, 23rd October 2008 was a Wednesday.