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Calculate the moles of solute needed to prepare each of the following solutions: a) 450 mL of 0.20 M KBr solution. b) 2.0 L of 1.5 M NaOH solutionGroup of answer choices0.090 mol and 3 mol6 mol , and 1.8 molenone of the above1.8 mol, and 6 mol3 mol, and 0.09 mole

Question

Calculate the moles of solute needed to prepare each of the following solutions: a) 450 mL of 0.20 M KBr solution. b) 2.0 L of 1.5 M NaOH solutionGroup of answer choices0.090 mol and 3 mol6 mol , and 1.8 molenone of the above1.8 mol, and 6 mol3 mol, and 0.09 mole

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Solution

Para calcular los moles de soluto necesarios para preparar las soluciones dadas, utilizamos la fórmula de la molaridad (M):

Molaridad (M)=moles de solutolitros de solucioˊn \text{Molaridad (M)} = \frac{\text{moles de soluto}}{\text{litros de solución}}

a) Para 450 mL de una solución de 0.20 M de KBr:

  1. Convertimos 450 mL a litros: 450mL=0.450L 450 \, \text{mL} = 0.450 \, \text{L}

  2. Usamos la fórmula de la molaridad para encontrar los moles de KBr: 0.20M=moles de KBr0.450L 0.20 \, \text{M} = \frac{\text{moles de KBr}}{0.450 \, \text{L}}

  3. Despejamos los moles de KBr: moles de KBr=0.20M×0.450L \text{moles de KBr} = 0.20 \, \text{M} \times 0.450 \, \text{L} moles de KBr=0.090mol \text{moles de KBr} = 0.090 \, \text{mol}

b) Para 2.0 L de una solución de 1.5 M de NaOH:

  1. Usamos la fórmula de la molaridad para encontrar los moles de NaOH: 1.5M=moles de NaOH2.0L 1.5 \, \text{M} = \frac{\text{moles de NaOH}}{2.0 \, \text{L}}

  2. Despejamos los moles de NaOH: moles de NaOH=1.5M×2.0L \text{moles de NaOH} = 1.5 \, \text{M} \times 2.0 \, \text{L} moles de NaOH=3.0mol \text{moles de NaOH} = 3.0 \, \text{mol}

Por lo tanto, las respuestas son:

a) 0.090 mol de KBr

b) 3.0 mol de NaOH

La opción correcta es: 0.090 mol y 3 mol

This problem has been solved

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