if(t2.seconds > t1.seconds) { --t1.minutes; t1.seconds += 60; } difference->seconds = t1.seconds - t2.seconds; if(t2.minutes > t1.minutes) { --t1.hours; t1.minutes += 60; } difference->minutes = t1.minutes-t2.minutes; difference->hours = t1.hours-t2.hours;}

Create a Time class and initialize it with hours and minutes.1. Make a method addTime which should take two time object and add them. E.g.- (2 hour and 50 min)+(1 hr and 20 min) is (4 hr and 10 min)2. Make a method displayTime which should print the time.3. Make a method DisplayMinute which should display the total minutes in the Time. E.g.- (1 hr 2 min) should display 62 minute.

elect the correct answerHow to get difference between two dates?OptionsDate diffInMilli = java.time.Duration.between(dateTime1, dateTime2).toMillis();long diffInMilli = java.time.difference(dateTime1, dateTime2).toMillis();long diffInMilli = java.time.Duration.between(dateTime1, dateTime2).toMillis();Time diffInMilli = java.time.Duration.between(dateTime1, dateTime2).toMillis();

Write an if-else statement to output "Less than a minute" if the value of recordingLength is less than 60. Otherwise, output "At least a minute". End each output with a newline.Ex: If the input is 58, then the output is:Less than a minute

Two cars 220 km apart, are approaching each other.  One car is moving at 50 km/h while the other is moving at 60 km/h.  Find the time after which they will meet.

Develop a C++ program that uses a class called time A time is represented in hours, minutes and seconds. For example (3:35:50). Define three objects for time class and get the user input values for first object.  Initialize the second object using constructors. Set the third object equal to the sum of other two and display the value of the new timings using operator overloading, destructors and friend functions. Sample Input     3:35:504:30:20Sample Output: 8:06:10.