The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of 20 cm from its center is 1.5×10−5Tm. The magnetic moment of the dipole is _____ Am2. (Given : μ04π=10−7TmA−1)
Question
The magnetic potential due to a magnetic dipole at a point on its axis situated at a distance of 20 cm from its center is 1.5×10−5Tm. The magnetic moment of the dipole is _____ Am2. (Given : μ04π=10−7TmA−1)
Solution
The magnetic potential (V) due to a magnetic dipole at a point on its axis is given by the formula:
V = μ0/4π * 2M/r^3
where: μ0/4π = 10^-7 Tm/A (given) M = magnetic moment (what we're trying to find) r = distance from the center of the dipole = 20 cm = 0.2 m (given) V = magnetic potential = 1.5×10^-5 Tm (given)
We can rearrange the formula to solve for M:
M = V * r^3 / (2 * μ0/4π)
Substituting the given values:
M = 1.5×10^-5 Tm * (0.2 m)^3 / (2 * 10^-7 Tm/A)
M = 3×10^-2 Am^2
So, the magnetic moment of the dipole is 3×10^-2 Am^2.
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