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For the gaseous reaction 2A + B → C + D,rate = k[A][B]. The volume of the containercontaining the reaction mixture is suddenlyreduced to one fourth of its original volume.New rate with respect to original rate is :

Question

For the gaseous reaction 2A + B → C + D,rate = k[A][B]. The volume of the containercontaining the reaction mixture is suddenlyreduced to one fourth of its original volume.New rate with respect to original rate is :

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Solution

To determine the new rate with respect to the original rate, we need to consider the effect of the change in volume on the reaction rate.

According to the given reaction rate equation, rate = k[A][B], the rate of the reaction is directly proportional to the concentrations of reactants A and B.

When the volume of the container is suddenly reduced to one fourth of its original volume, the concentration of reactants A and B will increase by a factor of four. This is because the number of moles of reactants remains constant, but the volume in which they are contained has decreased.

Since the rate is directly proportional to the concentrations of reactants A and B, the new rate will also increase by a factor of four. Therefore, the new rate with respect to the original rate is 4:1.

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