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YouLet 2x^4 + 5x^3 + 3x^2 + 2x - 50 / x^4 + 3. What is the equation of the horizontal asymptote of f(x) and from what direction does f(x) approach the asymptote as x tends to positive infinity?

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YouLet 2x^4 + 5x^3 + 3x^2 + 2x - 50 / x^4 + 3. What is the equation of the horizontal asymptote of f(x) and from what direction does f(x) approach the asymptote as x tends to positive infinity?

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Solution

The equation of the horizontal asymptote of the function f(x) = (2x^4 + 5x^3 + 3x^2 + 2x - 50) / (x^4 + 3) is y = 2. This is because the degree of the numerator and the denominator are the same (both are 4), so the horizontal asymptote is the ratio of the leading coefficients, which is 2/1 = 2.

As x tends to positive infinity, f(x) approaches the asymptote from below. This is because the leading term of the numerator (2x^4) is less than the leading term of the denominator (x^4) when x is positive. Therefore, as x increases, the value of f(x) gets closer and closer to 2 from below.

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