In a 50 m race, A can give a start of 5 m to B and a start of 14 m to C. In the same race, how much start can B give to C?10 m11 m12 m13 mNone

In a 50 m race, A can give a start of 5 m to B. This means that A is 5 m faster than B.

Similarly, A can give a start of 14 m to C, meaning A is 14 m faster than C.

To find out how much start B can give to C, we subtract the distance B is behind A from the distance C is behind A.

So, 14 m (C is behind A) - 5 m (B is behind A) = 9 m.

Therefore, in the same race, B can give a start of 9 m to C.

The problem states that in a 50 m race, A can give a start of 5 m to B and a start of 14 m to C. This means that when A runs 50 m, B runs 45 m and C runs 36 m.

To find out how much start B can give to C, we need to find the difference in the distances they run when A runs 50 m.

So, the start B can give to C is 45 m (B's distance) - 36 m (C's distance) = 9 m.

Therefore, none of the provided options (10 m, 11 m, 12 m, 13 m) is correct. The correct answer is 9 m.

In a 50 m race, A can give a start of 5 m to B. This means A runs 50 m while B runs 45 m.

Similarly, A can give a start of 14 m to C. This means A runs 50 m while C runs 36 m.

Now, we need to find out how much start B can give to C.

Since A runs 50 m while B runs 45 m, the speed ratio of A to B is 50:45 or 10:9.

Similarly, since A runs 50 m while C runs 36 m, the speed ratio of A to C is 50:36 or 25:18.

Now, we can find the speed ratio of B to C by dividing the speed ratio of A to B by the speed ratio of A to C.

So, the speed ratio of B to C is (10:9) / (25:18) = (10/9) / (25/18) = (1018) / (925) = 180:225 = 4:5.

This means that when B runs 5 m, C runs 4 m.

So, in a 50 m race, B can give a start of 50 - 40 = 10 m to C.

So, the answer is 10 m.

In a 50 m race, A can give a start of 5 m to B. This means A runs 50 m while B runs 45 m.

Similarly, A can give a start of 14 m to C. This means A runs 50 m while C runs 36 m.

Now, we need to find out how much start B can give to C.

Since A runs 50 m while B runs 45 m, the speed ratio of A to B is 50:45 or 10:9.

Similarly, since A runs 50 m while C runs 36 m, the speed ratio of A to C is 50:36 or 25:18.

Now, we need to find the speed ratio of B to C. We can do this by dividing the speed ratio of A to C by the speed ratio of A to B.

So, the speed ratio of B to C is (25:18) / (10:9) = 5:4.

This means that when B runs 50 m, C runs 40 m.

Therefore, B can give a start of 10 m to C.

In a 50 m race, A can give a start of 5 m to B. This means A runs 50 m while B runs 45 m.

Similarly, A can give a start of 14 m to C. This means A runs 50 m while C runs 36 m.

Now, we need to find out how much start B can give to C.

Since A runs 50 m while B runs 45 m, the speed ratio of A to B is 50:45 or 10:9.

Similarly, since A runs 50 m while C runs 36 m, the speed ratio of A to C is 50:36 or 25:18.

Now, we can find the speed ratio of B to C by dividing the speed ratio of A to B by the speed ratio of A to C.

So, the speed ratio of B to C is (10:9) / (25:18) = 20:25 or 4:5.

This means that when B runs 50 m, C runs 45 m.

So, B can give a start of 5 m to C.

Therefore, the answer is None of the above.