7. Use the following, balanced equation for the question below:2KClO3(s) → 2KCl(s) + 3O2(g)How many moles of KClO3 will be needed to produce 15.0 moles of oxygen gas?10.0 moles KClO315.0 moles KClO322.5 moles of KClO330.0 moles of KClO3
Question
- Use the following, balanced equation for the question below:2KClO3(s) → 2KCl(s) + 3O2(g)How many moles of KClO3 will be needed to produce 15.0 moles of oxygen gas?10.0 moles KClO315.0 moles KClO322.5 moles of KClO330.0 moles of KClO3
Solution
From the balanced chemical equation, we can see that 2 moles of KClO3 produce 3 moles of O2.
Therefore, to find out how many moles of KClO3 are needed to produce 15.0 moles of O2, we can set up a proportion:
(2 moles KClO3 / 3 moles O2) = (x moles KClO3 / 15.0 moles O2)
Solving for x gives us:
x = (2 moles KClO3 / 3 moles O2) * 15.0 moles O2 = 10.0 moles KClO3
So, 10.0 moles of KClO3 will be needed to produce 15.0 moles of oxygen gas.
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