The price (P) of a block of rectangular marble varies directly as the cube of its length (l cm). Mr Chan spends $400 on a block of marble. He cuts it into two blocks of equal length. He then sells these two blocks of marble.how to find mr chan's profit or lose and his porfit% or loss%
Question
The price (P) of a block of rectangular marble varies directly as the cube of its length (l cm). Mr Chan spends $400 on a block of marble. He cuts it into two blocks of equal length. He then sells these two blocks of marble.how to find mr chan's profit or lose and his porfit% or loss%
Solution
To solve this problem, we need to understand the concept of direct variation and how it applies to this situation. Here are the steps:
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Since the price of the marble varies directly as the cube of its length, we can express this relationship as P = kl^3, where k is the constant of variation.
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Mr. Chan spends $400 on a block of marble. So, we can write this as 400 = kl^3.
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When Mr. Chan cuts the block of marble into two blocks of equal length, the length of each block becomes l/2.
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The price of each smaller block of marble would then be k*(l/2)^3 = k*l^3/8 = 400/8 = $50.
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Therefore, the total price for the two smaller blocks of marble would be 2*100.
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Mr. Chan originally spent 100. Therefore, he has a loss of 100 = $300.
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The percentage loss can be calculated as (Loss / Original price) * 100%. So, the percentage loss would be (400) * 100% = 75%.
So, Mr. Chan has a loss of $300 and a percentage loss of 75%.
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