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The price (P) of a block of rectangular marble varies directly as the cube of its length (l cm). Mr Chan spends $400 on a block of marble. He cuts it into two blocks of equal length. He then sells these two blocks of marble.how to find mr chan's profit or lose and his porfit% or loss%

Question

The price (P) of a block of rectangular marble varies directly as the cube of its length (l cm). Mr Chan spends $400 on a block of marble. He cuts it into two blocks of equal length. He then sells these two blocks of marble.how to find mr chan's profit or lose and his porfit% or loss%

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Solution

To solve this problem, we need to understand the concept of direct variation and how it applies to this situation. Here are the steps:

  1. Since the price of the marble varies directly as the cube of its length, we can express this relationship as P = kl^3, where k is the constant of variation.

  2. Mr. Chan spends $400 on a block of marble. So, we can write this as 400 = kl^3.

  3. When Mr. Chan cuts the block of marble into two blocks of equal length, the length of each block becomes l/2.

  4. The price of each smaller block of marble would then be k*(l/2)^3 = k*l^3/8 = 400/8 = $50.

  5. Therefore, the total price for the two smaller blocks of marble would be 2*50=50 = 100.

  6. Mr. Chan originally spent 400andhesellsthetwosmallerblocksfor400 and he sells the two smaller blocks for 100. Therefore, he has a loss of 400400 - 100 = $300.

  7. The percentage loss can be calculated as (Loss / Original price) * 100%. So, the percentage loss would be (300/300 / 400) * 100% = 75%.

So, Mr. Chan has a loss of $300 and a percentage loss of 75%.

This problem has been solved

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