Let AB be the chord 4x−3y+5=0 of the circle x2+y2−2x+4y−20=0.If C=(7,1) then the area of triangle ABC is

The area of the triangle ABC with the vertices A(–5, 7), B(–4, –5) and C(4, 5) is

triangle ABC has side-lengths |AB|=5,|BC|=6,|CA|=7. Find the triangles area.

Find the area of the triangle whose vertices are (1, 2), (3, 7) and (5, 3).

Equation of a diameter of the circum circle of the triangle formed by the lines3x + 4y – 7=0, 3x – y + 5 = 0 and 8x – 6y + 1 = 0 is

Consider a right angled triangle with in-radius is 2 cm and circum radius of 7 cm. What is the area of triangle?