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In the titration of the mixture of the strong base, OH- ions and the weaker base, CO32- ions, againstHCl, using the phenolphthalein indicator, the weaker base is first converted to_______A. H2O2B. HNO3-C. HCO3-D. H3O+

Question

In the titration of the mixture of the strong base, OH- ions and the weaker base, CO32- ions, againstHCl, using the phenolphthalein indicator, the weaker base is first converted to_______A. H2O2B. HNO3-C. HCO3-D. H3O+

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Solution 1

In the titration of a mixture of a strong base (OH-) and a weaker base (CO32-) against HCl using the phenolphthalein indicator, the weaker base (CO32-) is first converted to HCO3-. So, the correct answer is C. HCO3-.

Here's the step-by-step explanation:

  1. The titration starts with the addition of HCl to the mixture of OH- and CO32-.

  2. The strong base OH- reacts first with HCl because it is more reactive than the weak base CO32-. The reaction is: OH- + HCl -> H2O + Cl-.

  3. After all the OH- ions have reacted, the HCl starts to react with the weaker base CO32-. The reaction is: CO32- + HCl -> HCO3- + Cl-.

  4. The phenolphthalein indicator changes color, indicating that all the OH- ions have reacted and the reaction with CO32- has started.

  5. The titration continues until all the CO32- ions have been converted to HCO3-. At this point, the phenolphthalein indicator changes color again, indicating the end of the titration.

This problem has been solved

Solution 2

In the titration of a mixture of a strong base (OH-) and a weaker base (CO32-) against HCl using the phenolphthalein indicator, the weaker base (CO32-) is first converted to HCO3-.

Here's the step-by-step explanation:

  1. The titration starts with the addition of HCl to the mixture of OH- and CO32-.

  2. The strong base (OH-) reacts first with HCl because it is more reactive than the weaker base (CO32-). The reaction is: OH- + HCl -> H2O + Cl-.

  3. After all the OH- ions have reacted, the HCl starts to react with the weaker base (CO32-).

  4. The reaction between HCl and CO32- is: CO32- + HCl -> HCO3- + Cl-.

  5. Therefore, in the titration of the mixture of OH- and CO32- against HCl, the weaker base (CO32-) is first converted to HCO3-.

So, the correct answer is C. HCO3-.

This problem has been solved

Solution 3

In a titration of a mixture of a strong base (OH-) and a weaker base (CO32-) against HCl using phenolphthalein as an indicator, the weaker base (CO32-) reacts first. The reaction is as follows:

CO32- + HCl -> HCO3- + Cl-

So, the weaker base CO32- is first converted to HCO3-. Therefore, the correct answer is C. HCO3-.

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