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Observe the below code :class Parent  {      public void display() {                System.out.println("Parent");      }}class Child extends Parent  {      public void display() {                System.out.println("Child");      }}public class Main  {       public static void main(String args[ ])   {               Parent p =   ;               Child  c = ;               p.display();  c.display();       }}Fill the code accordingly, so that you get the output asChildChild.

Question

Observe the below code :class Parent  {      public void display() {                System.out.println("Parent");      }}class Child extends Parent  {      public void display() {                System.out.println("Child");      }}public class Main  {       public static void main(String args[ ])   {               Parent p =   ;               Child  c = ;               p.display();  c.display();       }}Fill the code accordingly, so that you get the output asChildChild.

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Solution

The code should be filled as follows:

class Parent { 
    public void display() { 
        System.out.println("Parent"); 
    }
}

class Child extends Parent { 
    public void display() { 
        System.out.println("Child"); 
    }
}

public class Main { 
    public static void main(String args[ ]) { 
        Parent p = new Child(); 
        Child c = new Child(); 
        p.display(); 
        c.display(); 
    }
}

In this code, we are creating objects of Child class and assigning them to Parent and Child class references. When we call the display() method, it calls the Child class's display() method because of the concept of method overriding in Java. This is why the output will be Child Child.

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