What is the equation of the line that passes throughthe point (0, 5) and is parallel to the graph ofy = 7x + 4 in the xy-plane?A) y = 5xB) y = 7x + 5C) y = 7xD) y = 5x + 7
Question
What is the equation of the line that passes throughthe point (0, 5) and is parallel to the graph ofy = 7x + 4 in the xy-plane?A) y = 5xB) y = 7x + 5C) y = 7xD) y = 5x + 7
Solution
The equation of a line in the slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
Given that the line is parallel to the graph of y = 7x + 4, it will have the same slope. So, m = 7.
The line passes through the point (0, 5). This point is the y-intercept of the line, so b = 5.
Substituting m and b into the equation, we get y = 7x + 5.
So, the equation of the line is y = 7x + 5.
Therefore, the answer is B) y = 7x + 5.
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