To calculate the heat absorbed by the solution you:Question 3Select one:multiply the specific heat capacity of the solution by the temperature change. multiply the calorimeter constant by the temperature change.multiply the mass of the solution by its specific heat capacity and by the temperature change. multiply the calorimeter constant by the mass of the calorimeter and by the temperature change.

The heat associated with the reaction which happens in the calorimeter is calculated by:Question 4Select one:adding the heat absorbed by the calorimeter to the heat absorbed by the solutiontaking the heat absorbed by the solution, and then changing the signtaking the heat absorbed by the calorimeter and then changing the signadding the heat absorbed by the calorimeter to the heat absorbed by the solution, and then changing the sign

An insulated calorimeter contains 100 g of water at 10 °C. A salt is added to the solution, causing the temperature to drop by 3.0 °C. Given that water has a specific heat of 4.184 J/g°C, how much heat was transferred to or from the water?Group of answer choices1.3 kJ3.4 kJ4.2 kJ2.9 kJ

A piece of metal weighing 10.0 g is heated to raise its temperature from 25.0 °C to 76.5 °C. It is found that the metal absorbed 47.6 cal of heat in the process.(4pts)a. Calculate the specific heat of the metal. Include appropriate units.Note that mis mass of solution in Equation 8.1.

A certain chemical reaction releases 497.kJ of heat energy per mole of reactant consumed. Suppose some moles of the reactant are put into a calorimeter (a device for measuring heat flow). It takes 4.32J of heat energy to raise the temperature of this calorimeter by 1°C. Now the reaction is run until all the reactant is gone, and the temperature of the calorimeter is found to rise by 12.8°C. How would you calculate the number of moles of reactant that were consumed?Set the math up. But don't do any of it. Just leave your answer as a math expression.Also, be sure your answer includes all the correct unit symbols.

Which one of the following equation is correct*Heat given by hot water + heat taken by cold water = heat taken by calorimeterHeat given by hot water - heat taken by cold water = heat taken by calorimeterHeat taken by cold water = heat taken by calorimeter + Heat given by hot waterHeat taken by hot water - heat given by cold water = Heat taken by calorimeter