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Express ln(โˆš๐‘ฅ๐‘ฆ ) in terms of ln ๐‘ฅ and ln ๐‘ฆ:

Question

Express ln(โˆš๐‘ฅ๐‘ฆ ) in terms of ln ๐‘ฅ and ln ๐‘ฆ:

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Solution

To express ln(โˆš๐‘ฅ๐‘ฆ ) in terms of ln ๐‘ฅ and ln ๐‘ฆ, we can use the properties of logarithms. Here are the steps:

  1. First, recognize that โˆš๐‘ฅ๐‘ฆ is the same as (๐‘ฅ๐‘ฆ)^(1/2). So, ln(โˆš๐‘ฅ๐‘ฆ ) becomes ln((๐‘ฅ๐‘ฆ)^(1/2)).

  2. Use the power rule of logarithms, which states that ln(a^b) = b*ln(a). Applying this rule, ln((๐‘ฅ๐‘ฆ)^(1/2)) becomes (1/2)*ln(๐‘ฅ๐‘ฆ).

  3. Now, use the product rule of logarithms, which states that ln(ab) = ln(a) + ln(b). Applying this rule, (1/2)ln(๐‘ฅ๐‘ฆ) becomes (1/2)(ln(๐‘ฅ) + ln(๐‘ฆ)).

  4. Finally, distribute the 1/2 to both ln(๐‘ฅ) and ln(๐‘ฆ) to get (1/2)*ln(๐‘ฅ) + (1/2)*ln(๐‘ฆ).

So, ln(โˆš๐‘ฅ๐‘ฆ ) in terms of ln ๐‘ฅ and ln ๐‘ฆ is (1/2)*ln(๐‘ฅ) + (1/2)*ln(๐‘ฆ).

This problem has been solved

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