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When two numbers are separately divided by 33, the remainders are 21 and 28 respectively. If the sum of the two numbers is divided by 33, the remainder will beOptions10141612

Question

When two numbers are separately divided by 33, the remainders are 21 and 28 respectively. If the sum of the two numbers is divided by 33, the remainder will beOptions10141612

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Solution

To solve this problem, we can use the concept of remainders and modular arithmetic.

Let's call the two numbers x and y. We know that when x is divided by 33, the remainder is 21, and when y is divided by 33, the remainder is 28.

Using modular arithmetic, we can express these conditions as equations: x ≡ 21 (mod 33) y ≡ 28 (mod 33)

Now, let's find the sum of x and y: x + y ≡ 21 + 28 (mod 33) x + y ≡ 49 (mod 33)

To find the remainder when the sum of x and y is divided by 33, we need to find the smallest non-negative integer that is congruent to 49 modulo 33.

To do this, we can divide 49 by 33: 49 ÷ 33 = 1 remainder 16

Therefore, the remainder when the sum of x and y is divided by 33 is 16.

So, the correct option is 16.

This problem has been solved

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