The wavelength of the first overtone of a note in a closed pipe of length 33 cm is?
Question
The wavelength of the first overtone of a note in a closed pipe of length 33 cm is?
Solution
Sure, here is the step by step solution:
-
First, we need to understand that in a closed pipe, the first overtone is the third harmonic. This is because a closed pipe only produces odd harmonics.
-
The formula for the wavelength of a harmonic in a closed pipe is given by: λ = 4L/n, where L is the length of the pipe and n is the harmonic number.
-
Substituting the given values into the formula, we get: λ = 4 * 33 cm / 3 = 44 cm.
So, the wavelength of the first overtone of a note in a closed pipe of length 33 cm is 44 cm.
Similar Questions
Difference between the resonance lengths of two successive overtones of a tube closed at one end was 32 cm.If the end correction of the tube is 0.5 cm, what is the resonance length of the pipe when it vibrates at it’sfundamental frequency?
A 30 cm long organ pipe is filled with air and is open at one end and closed at the other. The speed of sound in air at 0°C is 331 m/s. What is the wavelength of the second mode of vibration?
A tuning fork resonates with the note A, which hasa period of 0.00226 s and a wave speed of 343.2 m/s.What is the wavelength, in centimetres, of the note A?
A 20 cm long organ pipe is filled with air and is open at one end and closed at the other. The speed of sound in air at 0°C is 331 m/s. What is the wavelength of the fundamental mode?
The air in an adjustable pipe open at one end and closed at the other resonates at the fundamental frequency when the pipe has length L0. The pipe is then adjusted such that it is twice its original length. What is the wavelength of the air in the pipe at the new fundamental frequency?A.L0B.2L0C.4L0D.8L0
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.