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Find all angles, 0, degrees, is less than or equal to, B, is less than, 360, degrees0 ∘ ≤B<360 ∘ , that satisfy the equation below, to the nearest tenth of a degree (if necessary).minus, tangent, B, minus, 5, equals, tangent, B, minus, 4−tanB−5=tanB−4

Question

Find all angles, 0, degrees, is less than or equal to, B, is less than, 360, degrees0 ∘ ≤B<360 ∘ , that satisfy the equation below, to the nearest tenth of a degree (if necessary).minus, tangent, B, minus, 5, equals, tangent, B, minus, 4−tanB−5=tanB−4

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Solution

The given equation is -tanB - 5 = tanB - 4.

Step 1: Combine like terms.

This gives us 2tanB = 1.

Step 2: Solve for B.

Divide both sides by 2 to isolate tanB. This gives us tanB = 1/2.

Step 3: Find the angle B.

Use the inverse tangent function to find the angle. B = arctan(1/2).

Step 4: Convert to degrees.

B = arctan(1/2) * (180/π) ≈ 26.6 degrees.

Step 5: Find all angles between 0 and 360 degrees.

The tangent function has a period of 180 degrees, so we add 180 to our initial solution to find the next solution in the specified range.

B = 26.6 + 180 = 206.6 degrees.

So, the angles that satisfy the equation are B = 26.6 degrees and B = 206.6 degrees.

This problem has been solved

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