Consider the following code. Assume that copy has been imported.w = [1, 2]z = copy.copy(w)z = copy.deepcopy(w)print(z + w)z = wwhy there are 3 different objects will exist in the computer’s memory after the code has been executed?Assume that no optimizations have been performed and that garbage collection has been executed.

The three different objects exist in the computer's memory due to the way Python handles object assignment and copying. Here's a step-by-step explanation:

1. w = [1, 2]: This line creates a list object [1, 2] and assigns it to the variable w. This is the first object in memory.

2. z = copy.copy(w): This line creates a shallow copy of w and assigns it to z. A shallow copy creates a new object, but fills it with references to the original object's elements if they are complex objects (like lists or class instances). However, since w only contains immutable objects (integers), the shallow copy is equivalent to a deep copy in this case. This is the second object in memory.

3. z = copy.deepcopy(w): This line creates a deep copy of w and assigns it to z. A deep copy creates a new object and recursively adds copies of the original object's elements to it. This is the third object in memory.

4. print(z + w): This line doesn't create any new objects, it just prints the concatenation of z and w.

5. z = w: This line doesn't create a new object either. It just assigns the reference of the object w to z. Now, z and w point to the same object in memory.

So, after the code has been executed, there are three different objects in memory: the original list [1, 2] assigned to w, the shallow copy of w, and the deep copy of w.