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Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.You may assume that each input would have exactly one solution, and you may not use the same element twice.You can return the answer in any order

Question

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.You may assume that each input would have exactly one solution, and you may not use the same element twice.You can return the answer in any order

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Solution

Sure, here is a Python solution using a dictionary to store the numbers and their indices.

def twoSum(nums, target):
    num_dict = {}
    for i, num in enumerate(nums):
        if target - num in num_dict:
            return [num_dict[target - num], i]
        num_dict[num] = i

Here's how it works:

  1. We define a function twoSum that takes a list of numbers (nums) and a target number (target) as input.

  2. We create an empty dictionary num_dict to store the numbers from the list and their indices.

  3. We start a loop that goes through each number in the list. For each number, we do the following:

    • We check if target - num is in num_dict. If it is, that means we

This problem has been solved

Similar Questions

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.

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