Consider a bright fringe in a two slit interference pattern. If we look at this point and double the wavelength of the light used in the two slit experiment (such that it still produces a pattern) what happens to this point?Question 4Answera.it remains a bright fringeb.it becomes a dark spotc.it would remain bright or become dark, depending on if the original m value was even or odd. d.it is impossible to tell.
Question
Consider a bright fringe in a two slit interference pattern. If we look at this point and double the wavelength of the light used in the two slit experiment (such that it still produces a pattern) what happens to this point?Question 4Answera.it remains a bright fringeb.it becomes a dark spotc.it would remain bright or become dark, depending on if the original m value was even or odd. d.it is impossible to tell.
Solution
The answer is a. it remains a bright fringe.
Here's why:
In a two-slit interference pattern, the bright fringes occur where the path difference between the two slits is an integer multiple of the wavelength. This is given by the formula dsin(theta) = mlambda, where d is the distance between the slits, theta is the angle to the fringe, m is an integer (the order of the fringe), and lambda is the wavelength of the light.
If we double the wavelength of the light, the path difference required for constructive interference (a bright fringe) also doubles. However, because the angle theta is also a variable in the equation, it's possible to adjust theta such that the equation still holds true. In other words, the bright fringe will move to a different location, but it will still be a bright fringe.
Therefore, even if we double the wavelength of the light, a bright fringe will remain a bright fringe, although its position will change.
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