Which one of the following does not define y as a function of x?Question 16Answera.x^2 + y = 16b.y = (x - 3)^2 - 1c.x = y^2d.x + y = 3
Question
Which one of the following does not define y as a function of x?Question 16Answera.x^2 + y = 16b.y = (x - 3)^2 - 1c.x = y^2d.x + y = 3
Solution
The option that does not define y as a function of x is c. x = y^2.
In this equation, for a single value of x, there can be two possible values of y (one positive and one negative). This violates the definition of a function, which states that for each input, there should be exactly one output. Therefore, option c does not define y as a function of x.
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