Find the product of the proper divisors of 720
Question
Find the product of the proper divisors of 720
Solution
Sure, let's find the product of the proper divisors of 720 step by step.
Step 1: Find the prime factorization of 720. 720 = 2^4 * 3^2 * 5
Step 2: Find all the divisors of 720. The divisors of 720 are the combinations of its prime factors. They are: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 30, 36, 40, 45, 48, 60, 72, 80, 90, 120, 144, 180, 240, 360, 720.
Step 3: Exclude the number itself (720) to get the proper divisors. The proper divisors of 720 are: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 30, 36, 40, 45, 48, 60, 72, 80, 90, 120, 144, 180, 240, 360.
Step 4: Find the product of the proper divisors. The product of the proper divisors of 720 is the product of all these numbers. However, calculating this directly would result in a very large number.
A more efficient way to calculate this is to realize that every divisor d of 720 pairs with a divisor 720/d to multiply to 720. Therefore, the product of all divisors of 720 is 720^(number of divisors / 2).
The number of divisors of 720 is 30 (including 720 itself), so the number of proper divisors is 29. Therefore, the product of the proper divisors of 720 is 720^(29/2), which is a very large number.
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