A standard containing ascorbic acid (25.0 mg mL-1) was analysed using reversed-phase HPLC with UV detection at 250 nm, giving a peak area of 34210. A sample containing ascorbic acid was then analysed under the same conditions, giving a peak area of 31622. Determine the concentration of ascorbic acid in the sample (in mg mL-1).
Question
A standard containing ascorbic acid (25.0 mg mL-1) was analysed using reversed-phase HPLC with UV detection at 250 nm, giving a peak area of 34210. A sample containing ascorbic acid was then analysed under the same conditions, giving a peak area of 31622. Determine the concentration of ascorbic acid in the sample (in mg mL-1).
Solution
To determine the concentration of ascorbic acid in the sample, we can use the standard to create a calibration curve, which in this case is a simple ratio since we only have one standard.
The ratio of the peak area to the concentration for the standard is:
34210 (peak area) / 25.0 mg/mL (concentration) = 1368.4 (area per unit concentration)
Now, we can use this ratio to find the concentration of ascorbic acid in the sample:
31622 (peak area of sample) / 1368.4 (area per unit concentration) = 23.1 mg/mL
So, the concentration of ascorbic acid in the sample is approximately 23.1 mg/mL.
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