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A standard containing ascorbic acid (25.0 mg mL-1) was analysed using reversed-phase HPLC with UV detection at 250 nm, giving a peak area of 34210.  A sample containing ascorbic acid was then analysed under the same conditions, giving a peak area of 31622.  Determine the concentration of ascorbic acid in the sample (in mg mL-1).

Question

A standard containing ascorbic acid (25.0 mg mL-1) was analysed using reversed-phase HPLC with UV detection at 250 nm, giving a peak area of 34210.  A sample containing ascorbic acid was then analysed under the same conditions, giving a peak area of 31622.  Determine the concentration of ascorbic acid in the sample (in mg mL-1).

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Solution

To determine the concentration of ascorbic acid in the sample, we can use the standard to create a calibration curve, which in this case is a simple ratio since we only have one standard.

The ratio of the peak area to the concentration for the standard is:

34210 (peak area) / 25.0 mg/mL (concentration) = 1368.4 (area per unit concentration)

Now, we can use this ratio to find the concentration of ascorbic acid in the sample:

31622 (peak area of sample) / 1368.4 (area per unit concentration) = 23.1 mg/mL

So, the concentration of ascorbic acid in the sample is approximately 23.1 mg/mL.

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