A perfect square trinomial is a trinomial that can be factored into the square of a binomial. The general form of a perfect square trinomial is (a+b)^2 = a^2 + 2ab + b^2.

In the given polynomial x^2 + 22x + ?, we can see that a = x and 2ab = 22x.

To find the value of b, we can set 2ab = 22x equal to 2*x*b and solve for b:

2*x*b = 22x
b = 22x / (2*x)
b = 11

So, the value of b^2 (which is the missing term in the trinomial) is 11^2 = 121.

Therefore, the value that makes the polynomial a perfect square trinomial is 121 (Option D).

Question

A perfect square trinomial is a trinomial that can be factored into the square of a binomial. The general form of a perfect square trinomial is (a+b)^2 = a^2 + 2ab + b^2.

In the given polynomial x^2 + 22x + ?, we can see that a = x and 2ab = 22x.

To find the value of b, we can set 2ab = 22x equal to 2*x*b and solve for b:

2*x*b = 22x
b = 22x / (2*x)
b = 11

So, the value of b^2 (which is the missing term in the trinomial) is 11^2 = 121.

Therefore, the value that makes the polynomial a perfect square trinomial is 121 (Option D).

Knowee AI · Accepted Answer

A perfect square trinomial is a trinomial that can be factored into the square of a binomial. The general form of a perfect square trinomial is (a+b)^2 = a^2 + 2ab + b^2.

In the given polynomial x^2 + 22x + ?, we can see that a = x and 2ab = 22x.

To find the value of b, we can set 2ab = 22x equal to 2*x*b and solve for b:

2*x*b = 22x
b = 22x / (2*x)
b = 11

So, the value of b^2 (which is the missing term in the trinomial) is 11^2 = 121.

Therefore, the value that makes the polynomial a perfect square trinomial is 121 (Option D).

What value in place of the question mark makes the polynomial below a perfect square trinomial?𝑥2+22𝑥+?x 2 +22x+?A.44B.11C.22D.121

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