The elastic potential energy (U) stored in a stretched or compressed spring is given by the formula:

U = 0.5 * k * x^2

where:
- k is the spring constant, and
- x is the amount the spring is stretched or compressed from its equilibrium position.

In this case, the spring constant k is 4 N/m and the spring is stretched by x = 0.5 m. Substituting these values into the formula gives:

U = 0.5 * 4 N/m * (0.5 m)^2
U = 0.5 * 4 N/m * 0.25 m^2
U = 0.5 * 1 N*m
U = 0.5 Joules

So, the spring gained 0.5 Joules of elastic potential energy.

Question

The elastic potential energy (U) stored in a stretched or compressed spring is given by the formula:

U = 0.5 * k * x^2

where:
- k is the spring constant, and
- x is the amount the spring is stretched or compressed from its equilibrium position.

In this case, the spring constant k is 4 N/m and the spring is stretched by x = 0.5 m. Substituting these values into the formula gives:

U = 0.5 * 4 N/m * (0.5 m)^2
U = 0.5 * 4 N/m * 0.25 m^2
U = 0.5 * 1 N*m
U = 0.5 Joules

So, the spring gained 0.5 Joules of elastic potential energy.

Knowee AI · Accepted Answer

The elastic potential energy (U) stored in a stretched or compressed spring is given by the formula:

U = 0.5 * k * x^2

where:
- k is the spring constant, and
- x is the amount the spring is stretched or compressed from its equilibrium position.

In this case, the spring constant k is 4 N/m and the spring is stretched by x = 0.5 m. Substituting these values into the formula gives:

U = 0.5 * 4 N/m * (0.5 m)^2
U = 0.5 * 4 N/m * 0.25 m^2
U = 0.5 * 1 N*m
U = 0.5 Joules

So, the spring gained 0.5 Joules of elastic potential energy.

A spring with a spring constant of 4 N/m is stretched by 0.5 m.How much elastic potential energy did it gain?