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Consider the function ๐‘“(๐‘ฅ)=๐‘ฅ3โˆ’6โ‹…๐‘ฅ2. Find the relevant curve sketching information and then select the correct graph from the list below.

Question

Consider the function ๐‘“(๐‘ฅ)=๐‘ฅ3โˆ’6โ‹…๐‘ฅ2. Find the relevant curve sketching information and then select the correct graph from the list below.

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Solution

To sketch the graph of the function ๐‘“(๐‘ฅ)=๐‘ฅยณโˆ’6โ‹…๐‘ฅยฒ, we need to find the following information:

  1. Domain and Range
  2. Intercepts
  3. Critical points
  4. Inflection points
  5. Asymptotes
  6. End behavior

Let's find these step by step:

  1. Domain and Range: The domain of a polynomial function is all real numbers, so the domain of this function is (-โˆž, โˆž). The range of a cubic function is also all real numbers, so the range is also (-โˆž, โˆž).

  2. Intercepts: To find the x-intercepts, set ๐‘“(๐‘ฅ) = 0 and solve for x. ๐‘ฅยณโˆ’6โ‹…๐‘ฅยฒ = 0 ๐‘ฅยฒ(๐‘ฅโˆ’6) = 0 So, x = 0 and x = 6 are the x-intercepts. The y-intercept is found by setting x = 0 in the function, so y = 0.

  3. Critical points: These are found by taking the derivative of the function and setting it equal to zero. ๐‘“'(๐‘ฅ) = 3๐‘ฅยฒ - 12๐‘ฅ = 0 3๐‘ฅ(๐‘ฅ - 4) = 0 So, x = 0 and x = 4 are the critical points.

  4. Inflection points: These are found by taking the second derivative of the function and setting it equal to zero. ๐‘“''(๐‘ฅ) = 6๐‘ฅ - 12 = 0 So, x = 2 is the inflection point.

  5. Asymptotes: Since this is a polynomial function, it does not have any vertical or horizontal asymptotes.

  6. End behavior: Since the leading term is ๐‘ฅยณ and the coefficient is positive, as x approaches -โˆž, ๐‘“(๐‘ฅ) approaches -โˆž and as x approaches โˆž, ๐‘“(๐‘ฅ) approaches โˆž.

Now, you can use this information to sketch the graph or select the correct graph from a list.

This problem has been solved

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