PASSAGEDirections Read the given passage carefully and find the answers of following questions. LCM of two numbers A and B is 60. B is a 2-digit number which leaves remainder as 2 when divided by 6. It is also given B>A.Read the instructions carefullyFind Maximum value of A+B.OPTIONS23323550
Question
PASSAGEDirections Read the given passage carefully and find the answers of following questions. LCM of two numbers A and B is 60. B is a 2-digit number which leaves remainder as 2 when divided by 6. It is also given B>A.Read the instructions carefullyFind Maximum value of A+B.OPTIONS23323550
Solution
To solve this problem, we need to follow these steps:
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Understand the given information:
- The Least Common Multiple (LCM) of two numbers and is 60.
- is a 2-digit number that leaves a remainder of 2 when divided by 6.
- is greater than .
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Identify possible values for :
- Since leaves a remainder of 2 when divided by 6, can be written as where is an integer.
- is a 2-digit number, so .
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List the possible values of :
- We need to find values of that fit the form and are within the range of 10 to 99.
- Possible values of are: 14, 20, 26, 32, 38, 44, 50, 56, 62, 68, 74, 80, 86, 92, 98.
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Determine the corresponding values of :
- Since the LCM of and is 60, must be a factor of 60.
- The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
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Check each possible to find the corresponding :
- For each , we need to check if there is a factor such that the LCM of and is 60 and .
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Calculate the maximum value of :
- We need to find the pair that satisfies the conditions and gives the maximum sum .
Let's go through the possible values of and find the corresponding :
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For :
- The factors of 60 that are less than 14 are: 1, 2, 3, 4, 5, 6, 10, 12.
- Check if the LCM of each factor with 14 is 60:
- LCM(10, 14) = 70 (not 60)
- LCM(12, 14) = 84 (not 60)
- LCM(6, 14) = 42 (not 60)
- LCM(5, 14) = 70 (not 60)
- LCM(4, 14) = 28 (not 60)
- LCM(3, 14) = 42 (not 60)
- LCM(2, 14) = 14 (not 60)
- LCM(1, 14) = 14 (not 60)
- No valid for .
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For :
- The factors of 60 that are less than 20 are: 1, 2, 3, 4, 5, 6, 10, 12, 15.
- Check if the LCM of each factor with 20 is 60:
- LCM(15, 20) = 60 (valid pair)
- , , .
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For :
- The factors of 60 that are less than 26 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20.
- Check if the LCM of each factor with 26 is 60:
- No valid for .
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Continue this process for other values of .
After checking all possible values, we find that the maximum value of is achieved with and , giving .
Therefore, the maximum value of is 35.
Answer: 35
Similar Questions
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