To help with a down payment on a home, Mai is going to invest. Assuming an interest rate of 1.62% compounded monthly, how much would she have to invest to have $36,800 after 6 years?
Question
To help with a down payment on a home, Mai is going to invest. Assuming an interest rate of 1.62% compounded monthly, how much would she have to invest to have $36,800 after 6 years?
Solution
To solve this problem, we need to use the formula for compound interest, which is:
A = P (1 + r/n)^(nt)
Where: A = the amount of money accumulated after n years, including interest. P = the principal amount (the initial amount of money) r = annual interest rate (in decimal) n = number of times that interest is compounded per year t = time the money is invested for in years
We know that A = $36,800, r = 1.62% or 0.0162 in decimal form, n = 12 (since the interest is compounded monthly), and t = 6 years. We want to find P.
Rearranging the formula to solve for P gives us:
P = A / (1 + r/n)^(nt)
Substituting the known values gives us:
P = $36,800 / (1 + 0.0162/12)^(12*6)
Now, we just need to calculate the right-hand side to find P.
P = $36,800 / (1 + 0.00135)^(72)
P = $36,800 / 1.093443
P = $33,643.47
So, Mai would need to invest approximately 36,800 after 6 years with an interest rate of 1.62% compounded monthly.
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